为什么51单片机读取DS12C887数据读不出来！

象牙塔 · 发表于 2012-10-28 16:47:02

51单片机DS12C887驱动问题？为什么读出的数据是零，而且显示的字乱跳呢，代码如下，不知道是不是代码问题

2012-10-27 11:25

#include<reg52.h>
#define uchar unsigned char 
#define uint unsigned int
sbit rs=P3^5;
sbit lcden=P3^4;
sbit lcdrw=P3^6;
sbit rd=P3^7;


sbit dscs=P1^4;
sbit dsas=P1^5;
sbit dsrw=P1^6;
sbit dsds=P1^7;
sbit dsirq=P3^3;


//uchar count,s1num,flag,flag1;
char miao,shi,fen;
uchar code table[]="  2007-7-30 MON";
uchar code table1[]="      :  :  ";
void write_ds(uchar,uchar);
void set_alarm(uchar,uchar,uchar);
uchar read_ds(uchar);void set_time();
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}




void write_com(uchar com)
{
rs=0;
lcden=0;
P0=com;
delay(5);
lcden=1;
delay(5);
lcden=0;
}


void write_date(uchar date)
{
rs=1;
lcden=0;
P0=date;
delay(5);
lcden=1;
delay(5);
lcden=0;
}


void init()
{
uchar num;




lcden=0;
lcdrw=0;
write_ds(0x0a,0x20);
set_time();
//set_alarm(14,13,10);
write_ds(0x0B,0x26);
//read_ds(0x0c);


write_com(0x38);
write_com(0x0c);
write_com(0x06);
write_com(0x01);
write_com(0x80);
for(num=0;num<15;num++)
{
write_date(table[num]);
delay(5);
}
write_com(0x80+0x40);
for(num=0;num<12;num++)
{
write_date(table1[num]);
delay(5);
}


}


void write_sfm(uchar add,uchar date)
{
uchar shi,ge;
shi=date/10;
ge=date%10;
write_com(0x80+0x40+add);
write_date(0x30+shi);
write_date(0x30+ge);
}


void write_ds(uchar add,uchar date)
{
dscs=0;
dsas=1;
dsds=1;
dsrw=1;
P0=add;
dsas=0;
dsrw=0;
P0=date;
dsrw=1;
dsas=1;
dscs=1;
}


uchar read_ds(uchar add)
{   
  uchar ds_date;
 dscs=0;
dsas=1;
dsds=1;
dsrw=1;
//    dscs=0;
P0=add;
dsas=0;
dsds=0;
P0=0xff;
ds_date=P0;
dsds=1;
dsas=1;
dscs=1;
return ds_date;
}


void set_time()
{
write_ds(4,10);
write_ds(2,32);
}


void set_alarm(uchar ashi,uchar afen,uchar amiao)
{
write_ds(1,amiao);
write_ds(3,afen);
write_ds(5,ashi);
}
void main()
{
init();
while(1)
{


miao=read_ds(0);
fen=read_ds(2);
shi=read_ds(4);
write_sfm(10,miao);
delay(2);
write_sfm(7,fen);
delay(2);
write_sfm(4,shi);
delay(2);

}
}
启动项也设置了？？？？[/mw_shl_code]