为什么进行按键程序操作时，只要使用u8 KEY_Scan(u8 mode)，按键就没有办法读取，如果不使用按键程序是有反应的？？

beibei · 发表于 2016-10-18 11:07:24

u8 KEY_Scan(u8 mode)
{
static u8 key_up=1;//按键按松开标志
if(mode==1)key_up=1;  //支持连按
if(key_up==1&&(KEY1==0||KEY2==0||KEY3==0||KEY4==0||KEY5==0||KEY6==0||KEY7==0||KEY8==0||KEY9==0||KEY10==0||KEY11==0||KEY13==0||KEY14==0))
{
delay_ms(10);//去抖动
key_up=0;
if(KEY1==0)return KEY1_PRES;
else if(KEY2==0)return KEY2_PRES;
else if(KEY3==0)return KEY3_PRES;
else if(KEY4==0)return KEY4_PRES;
else if(KEY5==0)return KEY5_PRES;
else if(KEY6==0)return KEY6_PRES;
else if(KEY7==0)return KEY7_PRES;
else if(KEY8==0)return KEY8_PRES;
else if(KEY9==0)return KEY9_PRES;
else if(KEY10==0)return KEY10_PRES;
else if(KEY11==0)return KEY11_PRES;
else if(KEY13==0)return KEY13_PRES;
else if(KEY14==0)return KEY14_PRES;
}
else if(KEY1==1&&KEY2==1&&KEY3==1&&KEY4==1&&KEY5==1&&KEY6==1&&KEY7==1&&KEY8==1&&KEY9==1&&KEY10==1&&KEY11==1&&KEY12==1&&KEY13==1&&KEY14==1)
{key_up=1;}
return 0;// 无按键按下

}
///////按键功能我利用keyprocess来实现
void KeyProcess(void){

    key=KEY_Scan(1);
if(key){
switch(key){
case KEY2_PRES:{
while(1){
SPI_I2S_SendData(SPI2, 0xABCD);
         }
   break;
}
}
}
}

//我的主函数主要程序
while(1){
if( USART_GetFlagStatus(USART2,USART_FLAG_TC) ){
i = USART_ReceiveData(USART2);
if( 0x12 == i ){
AllFlag.Welding = 1;
SendPara();
}
if( 0x21 == i ){
AllFlag.Welding = 0;
}
else
KeyProcess();
}
KeyProcess();

}
现在的问题主要就是只要使用了keyscan，按键就没有反应输出？？