stm32的GPIO位段问题

勤劳的小码农

[mw_shl_code=c,true]#define BITBAND (GPIO,PIN) ((GPIO&0xf0000000)+0x2000000+((GPIO&0xfffff)<<5+(PIN<<2))) #define MEM_ADDR(addr) *((volatile unsigned long * ) addr) #define BIT_Addr(GPIO,PIN) MEM_ADDR (BITBAND(GPIO,PIN) ) #define GPIOA_ODR_Addr GPIOA_BASE+12 #define GPIOB_ODR_Addr GPIOB_BASE+12 #define GPIOC_ODR_Addr GPIOC_BASE+12 #define GPIOD_ODR_Addr GPIOD_BASE+12 #define GPIOE_ODR_Addr GPIOE_BASE+12 #define GPIOF_ODR_Addr GPIOF_BASE+12 #define GPIOG_ODR_Addr GPIOG_BASE+12 #define GPIOA_IDR_Addr GPIOA_BASE+8 #define GPIOB_IDR_Addr GPIOB_BASE+8 #define GPIOC_IDR_Addr GPIOC_BASE+8 #define GPIOD_IDR_Addr GPIOD_BASE+8 #define GPIOE_IDR_Addr GPIOE_BASE+8 #define GPIOF_IDR_Addr GPIOF_BASE+8 #define GPIOG_IDR_Addr GPIOG_BASE+8 #define PAOut(PIN) BIT_Addr(GPIOA_ODR_Addr,PIN) #define PBOut(PIN) BIT_Addr(GPIOB_ODR_Addr,PIN) #define PCOut(PIN) BIT_Addr(GPIOC_ODR_Addr,PIN) #define PDOut(PIN) BIT_Addr(GPIOD_ODR_Addr,PIN)// BIT_Addr(GPIOD_ODR_Addr,PIN) #define PEOut(PIN) BIT_Addr(GPIOE_ODR_Addr,PIN) #define PFOut(PIN) BIT_Addr(GPIOF_ODR_Addr,PIN) #define PGOut(PIN) BIT_Addr(GPIOG_ODR_Addr,PIN) #define PAIn(PIN) BIT_Addr(GPIOA_IDR_Addr,PIN) #define PBIn(PIN) BIT_Addr(GPIOB_IDR_Addr,PIN) #define PCIn(PIN) BIT_Addr(GPIOC_IDR_Addr,PIN) #define PDIn(PIN) BIT_Addr(GPIOD_IDR_Addr,PIN) #define PEIn(PIN) BIT_Addr(GPIOE_IDR_Addr,PIN) #define PFIn(PIN) BIT_Addr(GPIOF_IDR_Addr,PIN) #define PGIn(PIN) BIT_Addr(GPIOG_IDR_Addr,PIN) int main() { GPIO_InitTypeDef gpio;

[mw_shl_code=c,true]PAOut(1)=1;[/mw_shl_code]

[/mw_shl_code]

为什么这个

[mw_shl_code=c,true]PAOut(1)=1;[/mw_shl_code]

就是不对啊

勤劳的小码农

回复【2楼】STM32VBT6:
------------------------------
问题不在这，我在宏定义里面就是大写“O”

STM32VBT6

小写吧？
应该是PAout(1)=1;