stm32串口发送16进制数据时到‘0’时，后面的数据就发不出去了

jiazaiguang · 发表于 2018-10-25 11:29:22

小弟初学stm32串口通信，想通过串口1发送：5A A5 07 82 00 84 5A 01 00 01这样一串16进制数据，串口1接受后用16进制显示为：
5A A5 07 82 00 84 5A 01 00 01;写了代码中的5组数据，只有最后一个数据不同，通过HAL_UART_Transmit（）发送，用串口助手
接受并√选Hex显示，结果只显示：5A A5 07 82;数据00及后面的数据无法输出了，请问大佬们是怎么回事啊？
int main(void)
{

  const char str1[]={0x5A,0xA5,0x07,0x82,0x00,0x84,0x5A,0x01,0x00,0x01};
  const char str2[]={0x5A,0xA5,0x07,0x82,0x00,0x84,0x5A,0x01,0x00,0x02};
  const char str3[]={0x5A,0xA5,0x07,0x82,0x00,0x84,0x5A,0x01,0x00,0x03};
  const char str4[]={0x5A,0xA5,0x07,0x82,0x00,0x84,0x5A,0x01,0x00,0x04};
  const char str5[]={0x5A,0xA5,0x07,0x82,0x00,0x84,0x5A,0x01,0x00,0x05};

HAL_Init();                   //初始化HAL库
Stm32_Clock_Init(336,8,2,8); //设置时钟,168Mhz
delay_init(168);             //初始化延时函数
LED_Init();                   //初始化LED
  uart_init(115200);             //初始化串口
  while(1)
{

HAL_UART_Transmit(&UART1_Handler,(uint8_t*)str1,strlen(str1),1000);
delay_ms(1000);
HAL_UART_Transmit(&UART1_Handler,(uint8_t*)str2,strlen(str2),1000);
delay_ms(1000);
HAL_UART_Transmit(&UART1_Handler,(uint8_t*)str3,strlen(str3),1000);
delay_ms(1000);
HAL_UART_Transmit(&UART1_Handler,(uint8_t*)str4,strlen(str4),1000);
delay_ms(1000);
HAL_UART_Transmit(&UART1_Handler,(uint8_t*)str5,strlen(str5),1000);
delay_ms(1000);
}
}