关于LCDL显示其它大小的字符的问题

dawenfly · 发表于 2013-12-4 22:42:22

字库为：
const unsigned char asc2_2412[95][36]={

{0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00},/*" ",0*/

{0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x0F,0x80,0x38,0x0F,0xFE,0x38,0x0F,0x80,0x38,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00},/*"!",1*/

{0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x06,0x00,0x00,0x0C,0x00,0x00,0x38,0x00,0x00,0x31,0x00,0x00,0x06,0x00,0x00,0x0C,0x00,0x00,0x38,0x00,0x00,0x30,0x00,0x00,0x00,0x00,0x00},/*""",2*/

{0x00,0x00,0x00,0x00,0x61,0x80,0x00,0x67,0xF8,0x07,0xF9,0x80,0x00,0x61,0x80,0x00,0x61,0x80,0x00,0x61,0x80,0x00,0x61,0x80,0x00,0x67,0xF8,0x07,0xF9,0x80,0x00,0x61,0x80,0x00,0x00,0x00},/*"#",3*/

{0x00,0x00,0x00,0x00,0x00,0x00,0x01,0xC0,0xE0,0x03,0xE0,0xF0,0x06,0x30,0x08,0x04,0x18,0x08,0x1F,0xFF,0xFE,0x04,0x0E,0x08,0x07,0x87,0xF0,0x03,0x81,0xE0,0x00,0x00,0x00,0x00,0x00,0x00},/*"$",4*/

{0x01,0xF0,0x00,0x06,0x0C,0x00,0x04,0x04,0x08,0x06,0x0C,0x70,0x01,0xF9,0xC0,0x00,0x0E,0x00,0x00,0x3B,0xE0,0x00,0xEC,0x18,0x07,0x08,0x08,0x04,0x0C,0x18,0x00,0x03,0xE0,0x00,0x00,0x00},/*"%",5*/

{0x00,0x01,0xE0,0x00,0x07,0xF0,0x03,0xF8,0x18,0x04,0x1C,0x08,0x04,0x17,0x08,0x07,0xE1,0xD0,0x03,0xC0,0xE0,0x00,0x23,0xB0,0x00,0x3C,0x08,0x00,0x20,0x08,0x00,0x00,0x10,0x00,0x00,0x00},/*"&",6*/
。。。。。。。。。。。。。。。。

void LCD_ShowChar(u16 x,u16 y,u8 num,u8 size,u8 mode)

{

u8 temp,t1,t;

u16 y0=y;

u16 colortemp=POINT_COLOR; //在显示前已定义好字体颜色

OINT_COLOR

//设置窗口

num=num-' ';//得到偏移后的值

if(!mode) //非叠加方式

{

for(t=0;t<size;t++)

{

if(size==12)temp=asc2_1206[num][t]; //调用1206字体

if(size==36)temp=asc2_2412[num][t]; //调用2412字体

else temp=asc2_1608[num][t]; //调用1608字体

。。。。。。。。。。。。。。。。。。。。。
显示为乱码
当用 if(size==24)temp=asc2_2412[num][t]; //调用2412字体
时，显示不完整（但不乱码），因为25～36丢失，

求解。。。。。。。。。。。不同大小的字符库要怎样用？