请教一个UCGUI动态显示图像的问题

某某网友 · 发表于 2017-9-27 11:53:42

最近在用stm32f103vct6加UCGUI做一个涉及导航的项目，原理是通过蓝牙串口接收的数据显示导航状态图标（左转右转直行箭头什么的），所以编程的思路想用UCGUI的位图显示功能，把图标图像转换成C文件，然后通过对比数据加载不同图标，但是由于图标太多，编译总是通不过，提示溢出。代码简单呈现如下：

extern const GUI_BITMAP  bmturn_back;
extern const GUI_BITMAP  bmturn_branch_center;
extern const GUI_BITMAP  bmturn_branch_left;
extern const GUI_BITMAP  bmturn_branch_right;
//…………定义图像，很多，省略
extern const GUI_BITMAP  bmturn_tollgate;

const int ShowIcon(char *str,int x,int y) {
      GUI_BITMAP tt1;
      int re = 0;
      if (strcmp(str,"turn_back")) { tt1=bmturn_back; re = 1;};//对比串口传输数据，加载图像显示
      if (strcmp(str,"turn_branch_center")) { tt1=bmturn_branch_center; re = 1; };
      if (strcmp(str,"turn_branch_left")) { tt1=bmturn_branch_left; re = 1; };
      if (strcmp(str,"turn_branch_right")) { tt1=bmturn_branch_right; re = 1; };
      if (strcmp(str,"turn_branch_right_straight")){ tt1=bmturn_branch_right_straight; re = 1; };
      if (strcmp(str,"turn_dest")) { tt1=bmturn_dest; re = 1; };
      if (strcmp(str,"turn_front")) { tt1=bmturn_front; re = 1; };
      if (strcmp(str,"turn_left_2branch_left")) { tt1=bmturn_left_2branch_left; re = 1; };
      if (strcmp(str,"turn_left_2branch_right")) { tt1=bmturn_left_2branch_right; re = 1; };
      if (strcmp(str,"turn_left_3branch_left")) { tt1=bmturn_left_3branch_left; re = 1; };
      if (strcmp(str,"turn_left_3branch_middle")) { tt1=bmturn_left_3branch_middle; re = 1; };
      if (strcmp(str,"turn_left_3branch_right")) { tt1=bmturn_left_3branch_right; re = 1; };
      if (strcmp(str,"turn_left_back")) { tt1=bmturn_left_back; re = 1; };
      if (strcmp(str,"turn_left_side")) {tt1=bmturn_left_side; re = 1};
      if  (strcmp(str,"turn_left_side_ic")) { tt1=bmturn_left_side_ic; re = 1;}
      if (strcmp(str,"turn_left_side_main")) { tt1=bmturn_left_side_main; re = 1};
      if (strcmp(str,"turn_right")) { tt1=bmturn_right; re = 1};
      if (strcmp(str,"turn_right_2branch_left")) { tt1=bmturn_right_2branch_left; re = 1;}
      if (strcmp(str,"turn_right_2branch_right")) {  tt1=bmturn_right_2branch_right; re = 1;}
      if (strcmp(str,"turn_right_3branch_left")) { tt1=bmturn_right_3branch_left; re = 1;}
      if (strcmp(str,"turn_right_3branch_middle")) { tt1=bmturn_right_3branch_middle; re = 1;}
      if (strcmp(str,"turn_right_3branch_right")) { tt1=bmturn_right_3branch_right; re = 1;}
      if (strcmp(str,"turn_right_back")) { tt1=bmturn_right_back; re = 1;}
      if (strcmp(str,"turn_right_front")) { tt1=bmturn_right_front; re = 1;}
      if (strcmp(str,"turn_right_side")) { tt1=bmturn_right_side;}
      if (strcmp(str,"turn_right_side_ic")) { tt1=bmturn_right_side_ic; re = 1;}
      if (strcmp(str,"turn_right_side_main")) { tt1=bmturn_right_side_main; re = 1;}
      if (strcmp(str,"turn_tollgate")) { tt1=bmturn_tollgate; re = 1;}
      if (re==1) GUI_DrawBitmap(&tt1,x,y);
      return re;
}

超过13个就会编译溢出，大量报错如下：
.\Output\Tiky_uCGUI_DEMO.axf: Error: L6406E: No space in execution regions with .ANY selector matching lcdinfo0.o(i.LCD_GetYSize).
请问除了更改硬件配置或者设计，还有没有其他方法实现类似功能？

lanlzp · 发表于 2017-9-27 11:53:43

出问题原因:
stm32f103vct6 FLASH区域总共256kb 你状态图标转换之后存储占用代码空间太多导致编译不通过,Error: L6406E: No space in execution regions with .ANY selector matching lcdinfo0.o(i.LCD_GetYSize).提示你没有可执行区域.
解决方案1:减少图片转换后的代码(会降低图片显示效果)
解决方案2:在不改动pcb板的情况下,可使用相同封装(pin to pin)大容量芯片替换,例如:stm32f103vet6(512kb flash)
解决方案3:如果允许改动pcb,则可增加外部flash芯片,将转换后的图片存储到外部flash

总之解决方式原则就是,在保证效果的情况下尽量减少图片转换后的代码量,否则就增加存储空间.