void task1_task(void *p_arg)
{
OS_ERR err;
u8 task1_str[]="First task Running!";
while(1)
{
printf("\r\n任务1:\r\n");
LCD_Fill(0,110,239,319,CYAN);
OSSemPend(&MY_SEM,0,OS_OPT_PEND_BLOCKING,0,&err);
memcpy(share_resource,task1_str,sizeof(task1_str));
delay_ms(300);
printf("%s\r\n",share_resource);
OSSemPost (&MY_SEM,OS_OPT_POST_1,&err);
LED0 = ~LED0;
OSTimeDlyHMSM(0,0,1,0,OS_OPT_TIME_PERIODIC,&err);
}
}
task1这个函数中在请求到信号量后,当执行到delay_ms(300);时会不会引发调度函数啊?后面还有个任务二
void task2_task(void *p_arg)
{
OS_ERR err;
u8 task2_str[]="Second task Running!";
while(1)
{
printf("\r\n任务2:\r\n");
LCD_Fill(0,110,239,319,BROWN);
OSSemPend(&MY_SEM,0,OS_OPT_PEND_BLOCKING,0,&err);
memcpy(share_resource,task2_str,sizeof(task2_str));
delay_ms(300);
printf("%s\r\n",share_resource);
OSSemPost (&MY_SEM,OS_OPT_POST_1,&err);
LED1 = ~LED1;
OSTimeDlyHMSM(0,0,1,0,OS_OPT_TIME_PERIODIC,&err);
}
}
|