这是我编的用数码管显示的温度传感器但不能用求各位大神帮忙看下

我爱和牛奶 · 发表于 2017-4-12 21:08:45

#include<reg52.h>
#include<stdio.h>
#include<intrins.h>
#include<delay us.h>

#define uint unsigned int
#define uchar unsigned char

sbit ds=P3^3;
sbit led1=P0^0;
sbit guan1=P2^7;
sbit guan2=P2^6;
sbit guan3=P2^5;
sbit guan4=P2^4;
uint shu[]={0Xc0,0Xf9,0Xa4,0Xb0,0X99,0X92,0X82,0Xf8,0X80,0X90};
uint shu1[]={0X40,0X79,0X24,0X30,0X19,0X12,0X02,0X78,0X00,0X10};
bit stuas;
int temp;
float f_temp;
uchar dat;

// ds18b20初始化
bit DS18b20_init(void)
{
ds=1;
_nop_();
ds=0;
Delay10us(65);
ds=1;
Delay10us(1);
while(!ds);
return stuas;
}

//写字节函数
void write_onebyte(uchar dat)
{
uchar i=0;
ds=1;
_nop_();
_nop_();
for(i=0;i<8;i++)
{
ds=0;
Delay10us(6);
ds=dat&0x01;
ds=1;
dat>>=1;
}
}
//读字节函数
uchar read_onebte(void)
{
uchar i=0,dat=0x00;
ds=1;
_nop_();
_nop_();
for(i=0;i<8;i++)
{
ds=0;
Delay6us();

ds=1;
_nop_();
_nop_();
_nop_();
dat>>=1;
if(ds)
{
ds |=0x80;
}
   Delay10us(3);
   ds=1;
}
return dat;
}

uint read_temp()
{
uchar a,b;
   DS18b20_init();
   write_onebyte(0xcc);
   write_onebyte(0x44); //发出温度转化命令

   DS18b20_init();
   write_onebyte(0xcc);
   write_onebyte(0xbe); //发出读温度命令
   a=read_onebte(); //读高8位
   b=read_onebte(); //读低8位
   temp=(uint)a;
   temp<<=8;
   temp=temp | (uint)b;
   f_temp=temp*0.0625;
   temp=f_temp*10+0.5;
   f_temp=f_temp+0.05;
   return temp;

}

void display(uint t)
{
uint ge,shi,bai,qian;
ge=t%10;
shi=t/10%10;
bai=t/100%10;
qian=t/1000;

   P1=shu[qian];
   guan1=0;
   Delay_ms(1);
   guan1=1;
   P1=0x00;

   P1=shu[bai];
   guan2=0;
   Delay_ms(1);
   guan2=1;
   P1=0x00;

   P1=shu1[shi];
   guan3=0;
   Delay_ms(1);
   guan3=1;
   P1=0x00;

   P1=shu[ge];
   guan4=0;
   Delay_ms(1);
   guan4=1;
   P1=0x00;
}

void main()
{
DS18b20_init();
while(1)
{
if(stuas==0)
{
read_temp();
display(read_temp());

}
else
{
DS18b20_init();
led1==0;
}

}

}