stm32利用寄存器如何开双串口（主要打开usart3中的PC10）

CallMeLEIGOD · 发表于 2016-5-16 18:46:19

#include "sys.h"
#include "usart3.h"
#include "stdarg.h"
#include "stdio.h"
#include "string.h"
#include "timer.h"
//////////////////////////////////////////////////////////////////////////////////
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//ALIENTEK STM32F103¿ª·¢°å
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//ÕýµãÔ×Ó@ALIENTEK
//¼¼ÊõÂÛÌ³:www.openedv.com
//ÐÞ¸ÄÈÕÆÚ:2015/3/14
//°æ±¾£ºV1.0
//°æÈ¨ËùÓÐ£¬µÁ°æ±Ø¾¿¡£
//Copyright(C) ¹ãÖÝÊÐÐÇÒíµç×Ó¿Æ¼¼ÓÐÏÞ¹«Ë¾ 2014-2024
//All rights reserved
//********************************************************************************
//ÐÞ¸ÄËµÃ÷
//ÎÞ
//////////////////////////////////////////////////////////////////////////////////

//´®¿Ú½ÓÊÕ»º´æÇø
u8 USART3_RX_BUF[USART3_MAX_RECV_LEN];                //½ÓÊÕ»º³å,×î´óUSART3_MAX_RECV_LEN¸ö×Ö½Ú.
u8  USART3_TX_BUF[USART3_MAX_SEND_LEN];          //·¢ËÍ»º³å,×î´óUSART3_MAX_SEND_LEN×Ö½Ú

//Í¨¹ýÅÐ¶Ï½ÓÊÕÁ¬Ðø2¸ö×Ö·ûÖ®¼äµÄÊ±¼ä²î²»´óÓÚ10msÀ´¾ö¶¨ÊÇ²»ÊÇÒ»´ÎÁ¬ÐøµÄÊý¾Ý.
//Èç¹û2¸ö×Ö·û½ÓÊÕ¼ä¸ô³¬¹ý10ms,ÔòÈÏÎª²»ÊÇ1´ÎÁ¬ÐøÊý¾Ý.Ò²¾ÍÊÇ³¬¹ý10msÃ»ÓÐ½ÓÊÕµ½
//ÈÎºÎÊý¾Ý,Ôò±íÊ¾´Ë´Î½ÓÊÕÍê±Ï.
//½ÓÊÕµ½µÄÊý¾Ý×´Ì¬
//[15]:0,Ã»ÓÐ½ÓÊÕµ½Êý¾Ý;1,½ÓÊÕµ½ÁËÒ»ÅúÊý¾Ý.
//[14:0]:½ÓÊÕµ½µÄÊý¾Ý³¤¶È
vu16 USART3_RX_STA=0;
void USART3_IRQHandler(void)
{
u8 res;
if(USART3->SR&(1<<5))//½ÓÊÕµ½Êý¾Ý
{
      res=USART3->DR;
      if((USART3_RX_STA&(1<<15))==0)//½ÓÊÕÍêµÄÒ»ÅúÊý¾Ý,»¹Ã»ÓÐ±»´¦Àí,Ôò²»ÔÙ½ÓÊÕÆäËûÊý¾Ý
      {
         if(USART3_RX_STA<USART3_MAX_RECV_LEN) //»¹¿ÉÒÔ½ÓÊÕÊý¾Ý
         {
            TIM7->CNT=0;                      //¼ÆÊýÆ÷Çå¿Õ
            if(USART3_RX_STA==0)                //Ê¹ÄÜ¶¨Ê±Æ÷7µÄÖÐ¶Ï
            {
                  TIM7->CR1|=1<<0;                //Ê¹ÄÜ¶¨Ê±Æ÷7
            }
            USART3_RX_BUF[USART3_RX_STA++]=res; //¼ÇÂ¼½ÓÊÕµ½µÄÖµ
         }else
         {
            USART3_RX_STA|=1<<15;             //Ç¿ÖÆ±ê¼Ç½ÓÊÕÍê³É
         }
      }
}
}
//³õÊ¼»¯IO ´®¿Ú3
//pclk1

CLK1Ê±ÖÓÆµÂÊ(Mhz)
//bound:²¨ÌØÂÊ
void usart3_init(u32 pclk1,u32 bound)
{
RCC->APB2ENR|=1<<3; //Ê¹Ä&#220

ORTB¿ÚÊ±ÖÓ
   GPIOB->CRH&=0XFFFF00FF; //IO×´Ì¬ÉèÖÃ
GPIOB->CRH|=0X00008B00; //IO×´Ì¬ÉèÖÃ

RCC->APB1ENR|=1<<18;    //Ê¹ÄÜ´®¿ÚÊ±ÖÓ
RCC->APB1RSTR|=1<<18; //¸´Î»´®¿Ú3
RCC->APB1RSTR&=~(1<<18);//Í£Ö¹¸´Î»
//²¨ÌØÂÊÉèÖÃ
   USART3->BRR=(pclk1*1000000)/(bound);// ²¨ÌØÂÊÉèÖÃ
USART3->CR1|=0X200C;    //1Î»Í£Ö¹,ÎÞÐ£ÑéÎ».
//Ê¹ÄÜ½ÓÊÕÖÐ¶Ï
USART3->CR1|=1<<5;       //½ÓÊÕ»º³åÇø·Ç¿ÕÖÐ¶ÏÊ¹ÄÜ
MY_NVIC_Init(0,1,USART3_IRQn,2);//×é2
TIM7_Int_Init(99,7199); //10msÖÐ¶Ï
TIM7->CR1&=~(1<<0);       //¹Ø±Õ¶¨Ê±Æ÷7
USART3_RX_STA=0;       //ÇåÁã
}

//´®¿Ú3,printf º¯Êý
//È·±£Ò»´Î·¢ËÍÊý¾Ý²»³¬¹ýUSART3_MAX_SEND_LEN×Ö½Ú
void u3_printf(char* fmt,...)
{
u16 i,j;
va_list ap;
va_start(ap,fmt);
vsprintf((char*)USART3_TX_BUF,fmt,ap);
va_end(ap);
i=strlen((const char*)USART3_TX_BUF);       //´Ë´Î·¢ËÍÊý¾ÝµÄ³¤¶È
for(j=0;j<i;j++)                         //Ñ»··¢ËÍÊý¾Ý
{
      while((USART3->SR&0X40)==0);          //Ñ»··¢ËÍ,Ö±µ½·¢ËÍÍê±Ï
      USART3->DR=USART3_TX_BUF[j];
}
}

利用这个从而可以使用PB10和PB9分别作为RXD TXD，但是现在我的PB10 PB9已经占用了，那如何使用映射的PC10 PC9。
void usart3_init(u32 pclk1,u32 bound)
{
RCC->APB2ENR|=1<<3;    //Ê¹Ä&#220

ORTB¿ÚÊ±ÖÓ
   GPIOB->CRH&=0XFFFF00FF; //IO×´Ì¬ÉèÖÃ
GPIOB->CRH|=0X00008B00; //IO×´Ì¬ÉèÖÃ

RCC->APB1ENR|=1<<18;    //Ê¹ÄÜ´®¿ÚÊ±ÖÓ
RCC->APB1RSTR|=1<<18; //¸´Î»´®¿Ú3
RCC->APB1RSTR&=~(1<<18);//Í£Ö¹¸´Î»
//²¨ÌØÂÊÉèÖÃ
   USART3->BRR=(pclk1*1000000)/(bound);// ²¨ÌØÂÊÉèÖÃ
USART3->CR1|=0X200C;    //1Î»Í£Ö¹,ÎÞÐ£ÑéÎ».
//Ê¹ÄÜ½ÓÊÕÖÐ¶Ï
USART3->CR1|=1<<5;       //½ÓÊÕ»º³åÇø·Ç¿ÕÖÐ¶ÏÊ¹ÄÜ
MY_NVIC_Init(0,1,USART3_IRQn,2);//×é2
TIM7_Int_Init(99,7199); //10msÖÐ¶Ï
TIM7->CR1&=~(1<<0);       //¹Ø±Õ¶¨Ê±Æ÷7
USART3_RX_STA=0;       //ÇåÁã
}

主要这里应该怎么改求大神指导啊