WCHAR ff_convert ( /* Converted code, 0 means conversion error */
WCHAR chr, /* Character code to be converted */
UINT dir /* 0: Unicode to OEMCP, 1: OEMCP to Unicode */
)
{
const WCHAR *p;
WCHAR c;
int i, n, li, hi;
if (chr < 0x80) { /* ASCII */
c = chr;
} else {
if (dir) { /* OEMCP to unicode */
p = oem2uni;
hi = sizeof(oem2uni) / 4 - 1;
} else { /* Unicode to OEMCP */
p = uni2oem;
hi = sizeof(uni2oem) / 4 - 1;
}
li = 0;
for (n = 16; n; n--) {
i = li + (hi - li) / 2;
if (chr == p[i * 2]) break; //
if (chr > p[i * 2])
li = i;
else
hi = i;
}
c = n ? p[i * 2 + 1] : 0;
}
return c;
}
以上函数查找UNICODE编码是用的二分法, hi = sizeof(oem2uni) / 4 - 1; 为什么要先除以4?? for (n = 16; n; n--) 为什么是16??
请大家指导,谢谢!
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