只能判断一次更新了快来人啊

poqpoqpoq90 · 发表于 2015-7-4 16:09:08

int main(void)
{       char i=0;
   Stm32_Clock_Init(9);           //?????±???è?? 72M
   uart2_init(36,9600);              //?®??????????9600
delay_init(72);
    while(1)
   {

       char r[200]={0xCA,0xBE,0xC0,0xC8,0xB5,0xC6,0xC1,0xC1,0xA3,0xAC,0xD4,0xB6,0xB9,0xE2,0xB5,0xC6,0xC1,0xC1};
       char q[200];
       char dat,w;
       while(!(USART2->SR & (1<<5)));
                       dat=USART2->DR ;
       q=dat;
           i++;


           if(strcmp(r,q)==0)
           {
               for(w=0;w<=i;w++)
               {
       while(!(USART2->SR & (1<<7)));
                       USART2->DR =q[w];
               }
               i=0;
               w=0;
           }
   }
}

只能判断一次怎搞啊
还有串口我直接赋值给u2串口只能用数组才能显示出来为什么直接给他个char类型都不行的
不是8个位传送多了的高位省略只取低8为嘛？
新手还望回答

xtayygtv · 发表于 2015-7-5 12:41:59

1、 char r[200]={0xCA,0xBE,0xC0,0xC8,0xB5,0xC6,0xC1,0xC1,0xA3,0xAC,0xD4,0xB6,0xB9,0xE2,0xB5,0xC6,0xC1,0xC1};
char q[200];
char dat,w;
这些变量的声明和赋值不要放在while循环里定义，放在系统时钟初始化前面
char q[200];
char dat,w;
char i=0;
char r[200]={0xCA,0xBE,0xC0,0xC8,0xB5,0xC6,0xC1,0xC1,0xA3,0xAC,0xD4,0xB6,0xB9,0xE2,0xB5,0xC6,0xC1,0xC1};
2、程序总在执行i++，等到再次接收数据时，i的值已经溢出