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关于字符串转换为十六进制数据类型的转换 |
10金钱
最佳答案int Year = (data[0]-'0')*1000+(data[1]-'0')*100+(data[2]-'0')*10+(data[3]-'0');
int Month = (data[3]-'0')*10+(data[3]-'0')
int Day = (data[5]-'0')*10+(data[6]-'0')
如此类推....
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