求助AVR看门狗反复复位问题

way7539512 · 发表于 2017-12-28 16:04:58

刚拿到新项目，叫用AVR单片机，用的ICC for AVR ，但是现在反复的被看门狗复位啊，因为用了熔丝，所以看门狗没办法关闭，现在是我不动他不复位，只要一操作按键就复位一次[mw_shl_code=c,true]//ICC-AVR application builder : 2017/12/26 15:39:41
// Target : M8
// Crystal: 4.0000Mhz

#include <iom8v.h>
#include <macros.h>

#include "usart.h"

u8 key_scan(void);

void watchdog_init(void)
{
WDR();
WDTCR = 0X1F;
WDTCR = 0X0F;
}

void port_init(void)
{
PORTB = 0x00;
DDRB  = 0x00;
PORTC = 0x1f;
DDRC  = 0x1f;
PORTD = 0x00;
DDRD  = 0x00;
}
void init_devices(void)
{
CLI();
port_init();
uart_init(51);//9600
watchdog_init();

MCUCR = 0x00;
GICR  = 0x00;
TIMSK = 0x00;
SEI();
}

void main(void)
{
//delay_ms(1000);
init_devices();
while(1)
{
  key_scan();
  WDR();
}
}

u8 key_scan(void)
{
  char flag=0;
  if(PIND&(1<<PIND2))//KEY1
  {
delay_ms(5);
if(PIND&(1<<PIND2))
{
   flag=1;
      uart_send(0x31);
      PORTC &= ~(1<<PORTC0);
      while(PIND&(1<<PIND2))WDR();
}
  }
  if(PINC&(1<<PINC5))//KEY2
  {
delay_ms(5);
if(PINC&(1<<PINC5))
{
   flag=2;
      uart_send(0x32);
      PORTC &= ~(1<<PORTC4);
      while(PINC&(1<<PINC5))WDR();
}
  }
  if(PIND&(1<<PIND3))//KEY3
  {
delay_ms(5);
if(PIND&(1<<PIND3))
{
   flag=3;
      uart_send(0x33);
      PORTC &= ~(1<<PORTC3);
      while(PIND&(1<<PIND3))WDR();
   }
  }
  if(PIND&(1<<PIND4))//KEY4
  {
delay_ms(5);
if(PIND&(1<<PIND4))
{
   flag=4;
      uart_send(0x34);
      PORTC &= ~(1<<PORTC2);
      while(PIND&(1<<PIND4))WDR();
}
  }
  if(PINB&(1<<PINB6))//KEY5
  {
delay_ms(5);
if(PINB&(1<<PINB6))
{
   flag=5;
      uart_send(0x35);
      PORTC &= ~(1<<PORTC1);
      while(PINB&(1<<PINB6))WDR();
}
  }
  return flag;
}
[/mw_shl_code]
求帮忙啊，现在一直找不到哪里触发的看门狗复位